X^2+6x=98

Solution for X^2+6x=98 equation:

X^2+6X=98

We move all terms to the left:

X^2+6X-(98)=0

a = 1; b = 6; c = -98;
Δ = b2-4ac
Δ = 62-4·1·(-98)
Δ = 428
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{428}=\sqrt{4*107}=\sqrt{4}*\sqrt{107}=2\sqrt{107}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{107}}{2*1}=\frac{-6-2\sqrt{107}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{107}}{2*1}=\frac{-6+2\sqrt{107}}{2}
$